Lesson Plan, Class XI (Ch-5) | Linear Inequalities

LESSON PLAN MATHEMATICS
CLASS - XI
CHapter - 5 : LINEAR INEQUALITIES

lesson plan for maths class XI cbse, lesson plans for mathematics teachers, lesson plan for maths teacher in B.Ed. Lesson Plan, Class XI  For Mathematics Teacher 

Rmb dav centnary public school Nawanshahr
NAME OF THE TEACHER				DINESH KUMAR
CLASS	10+1	CHAPTER	05	SUBJECT	MATHEMATICS
TOPIC	LINEAR INEQUALITIES			DURATION : 15 CLASS MEETINGS

TOPIC:
Chapter : 5 : Linear Inequalities

DURATION:
This chapter is divided into 10 modules and is completed in 10 class meetings.

PRE- REQUISITE KNOWLEDGE:

• Knowledge of number system,

• knowledge of representing the linear equations in two variables.

TEACHING AIDS:

Green Board, Chalk, Duster, Charts, smart board, projector, laptop etc.

METHODOLOGY:   

Lecture method  and Demonstration

LEARNING OBJECTIVES:

• Introduction of linear inequalities, different types of inequalities.

• Different types of intervals

• Algebraic solutions of linear inequalities in one variable and their representation on the number line.

LEARNING OUTCOMES:

After studying this lesson student should know 

• The different types of inequalities.

• Different types of intervals.

• Method of solving the linear inequalities and representing their solutions on the number line. 

RESOURCES

• NCERT Text Book,

• NCERT Exemplar Book of mathematics,

RESOURCE MATERIAL : 

Worksheets , E-content, Basics and formulas from  (cbsemathematics.com)

KEY WORDS

Linear Inequality, Algebraic Expression, Inequality Signs: <, >, ≤, ≥ ,  Solution / Solution Set, Variable (x, y, etc.), Domain of Solution , Linear Inequality in One Variable , Linear Inequality in two Variables, Standard Form: ax + b < 0, ax + by ≤ c

LEARNING ACTIVITIES:

INTRODUCTORY ACTIVITY

EXPERIENTIAL ACTIVITY

ART INTEGRATED ACTIVITY

PROCEDURE :

Start the session by asking the question related to the number system and about the method of representing the linear equations in two variables . Now introduce the topic Linear Inequalities in two variables step by step as follows.

CLICK HERE FOR 

[COMPLETE EXPLANATION]

Start the topic with the knowledge of number system, explain different types of numbers to the students.

Like : Natural number, whole number, Integers, rational numbers, real numbers etc.

Introduce the students with the linear inequalities and explain different types of inequalities.

If any two numbers or algebraic expressions are related with four symbols like   < , > ,  ≤ and  ≥  form an inequality.

If degree of the algebraic expression is 1 then it is called a linear inequality.

For example  2x - 3 ≤ 5,     2x+ 3 > 5  are the linear inequalities.

Explain the different types of intervals

Real solutions of inequality are represented in the form of  intervals. Intervals  are of 4 types

1. Open interval written as       (    )

2. Close Interval written as      [   ]

3.  Semi open or semi close interval written as   (    ]

4.  Semi open or semi close interval  written as  [     )

Now explain the method of finding the solution of linear inequalities and representation of the solution on the number line.

Real Number Line

Case 1: Graph of the line given below is called real number line

Real numbers start from -∞ and goes upto +∞

Set of real numbers are represented by  (-∞, ∞)

Case II

In the above graph O represent the open interval  at 1 and this solution is written as  (1, ∞)

Case III

In the above graph the dark spot represent the close interval at 1 and this solution is written as [1. ∞)

Case IV

Above solution can be written as  (-2, 3) it means  all terms between -2 and 3

Case V

Explain the method of diluting the given acidic material and complete procedure of solving such problems.

NCERT Miscellaneous Exercise

Q 12 :  A solution of 8% boric acid is to be diluted by adding a 2% boric acid solution to it. The resulting mixture is to be more than 4% but less than 6% boric acid. If we have 640 litres of the 8% solution, how many litres of the  2% solution will have to be added ?

Solution 

Amount of 8% boric acid solution = 640 litre

Let 2% boric acid solution added = x litre

Total solution becomes = (640 + x) litre

According to the question

4% (640 + x) ≤ 8% (640) + 2% of x ≤ 6% (640 + x)

Now solve this equation for the value of x

STUDENTS DELIVERABLES:

• Review questions given by the teacher. 

• Students should prepare the presentation individually or in groups on the method of representing the linear inequality, feasible reason  on the graph paper.  

• Solve NCERT problems with examples.

EXTENDED LEARNING:

Students can extend their learning in   through the Resource Centre Mathematics . Students can also find many interesting topics on mathematics at the site:   cbsemathematics.com

ASSESSMENT TECHNIQUES:

• Assignment sheet will be given as home work at the end of the topic. 

• Separate sheets which will include questions of logical thinking and Higher order thinking skills will be given to the above average students.

• Class Test , Oral Test , worksheet and Assignments. can be made the part of assessment.

• Re-test(s) will be conducted on the basis of the performance of the students in the test.

Competency based assessment can be taken so as to ensure if the learning outcomes have been achieved or not. e.g.

• Puzzle

• Quiz

• Misconception check

• Peer check

• Students discussion

• Competency Based Assessment link: M C Q