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How to solve a 3 x 3 Rubik's Cube  A Rubik’s Cube is a popular 3D combination puzzle invented in 1974 by ErnÅ‘ Rubik . It is made of small colored squares arranged on a cube. The most common version is the 3 × 3 × 3 cube , which has six colored sides. How it works Each side has 9 squares of the same color when solved. The rows and columns can be twisted and turned. The goal is to mix the colors and then return every side to a single color. Main Features Improves memory and concentration Develops problem-solving skills Enhances logical thinking and patienc Guidelines to solve the Rubik's Cube Step 1:  Put middle white at the base so that middle yellow is at the top 

Mathematics Lab Activity-10 Class XII

    Mathematics Lab Activity-10 Class XII

Mathematics Laboratory Activities 09 on Applications of Derivatives for class XI Non-Medical students with complete observation tables strictly according to the CBSE syllabus.

Chapter - 06 

applications of derivatives

Activity - 10

Objective

To find the time when the area of a rectangle of given dimensions become maximum, if the length is decreasing and breadth is increasing at given rates.

Material Required

Chart paper, paper cutter, scale, pencil, eraser, cardboard.

Procedure

1. Take a rectangle R1 of dimensions 16 cm x 8 cm.
2. Let the length of the rectangle is decreasing at the rate of 1cm/second and the breadth is increasing at the rate of 2cm/second.
3. Cut other rectangles R2 , R3 , R4, R5, R6 , R7, R8, R9, etc. of dimensions 15 cm x 10 cm, 14 cm x 12 cm, 13cm x 14 cm, 12 cm x 16 cm, 11 cm x 18 cm, 10cm x 20 cm, 9 cm x 22 cm, 8cm x 24 cm.
4. Paste all these rectangles on a card board as shown in figure 10.1.

Figure 10.1

5. The length of the rectangle decreasing at the rate of 1cm/s and breadth is increasing at the rate of 2 cm/s.
6. Area of the given rectangle R1 = 16 x 8 = 128 cm2.
7. Area of the given rectangle R2 = 15 x 10 = 150 cm2 (after 1 sec)
8. Area of the given rectangle R3 = 14 x 12 = 168 cm2 (after 2 sec)
9. Area of the given rectangle R4 = 13 x 14 = 182 cm2 (after 3 sec)
10. Area of the given rectangle R5 = 12 x 16 = 192 cm2 (after 4 sec)
11. Area of the given rectangle R6 = 11 x 18 = 198 cm2 (after 5 sec)
12. Area of the given rectangle R7 = 10 x 20 = 200 cm2 (after 6 sec)
13. Area of the given rectangle R8 = 9 x 22 = 198 cm2 (after 7 sec)

Observations

1. Area of the rectangle R1  = 128 cm2.

2. Area of the rectangle R2 (after 1 second) = 150 cm2.

3. Area of the rectangle R3 (after 2 second) = 168 cm2.

4. Area of the rectangle R4 (after 3 second) = 182 cm2.

5. Area of the rectangle R5 (after 4 second) = 192 cm2.

6. Area of the rectangle R6 (after 5 second) = 198 cm2.

7. Area of the rectangle R7 (after 6 second) = 200 cm2.

8. Area of the rectangle R8 (after 7 second) = 198 cm2.

9. Area of the rectangle is maximum after 6 seconds and the Maximum area of the rectangle is  200cm2

Result

Maximum area of the rectangle is 200cm2 after 6 seconds.

Applications

This activity is used in explaining the concept of rate of change of quantities

VIVA – VOICE

Q1. Define rate of change of function y = f(x)
Ans. If a quantity y varies with another quantity x such that y = f(x), then  equation  represents the rate of change of y w.r.t x.

Q2. What symbol is used to write rate of change of y w. r. t. t ?
Ans.  equation .

Q3. What symbol is used to write rate of change of y w. r. t. x ?
Ans. equation 

Q4. What is chain rule ?
Ans.  equation .


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