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How to solve a 3x3 Rubik's Cube

How to solve a 3 x 3 Rubik's Cube  A Rubik’s Cube is a popular 3D combination puzzle invented in 1974 by ErnÅ‘ Rubik . It is made of small colored squares arranged on a cube. The most common version is the 3 × 3 × 3 cube , which has six colored sides. How it works Each side has 9 squares of the same color when solved. The rows and columns can be twisted and turned. The goal is to mix the colors and then return every side to a single color. Main Features Improves memory and concentration Develops problem-solving skills Enhances logical thinking and patienc Guidelines to solve the Rubik's Cube Step 1:  Put middle white at the base so that middle yellow is at the top 

Mathematics Lab Activity-06 Class X | Arithmatic Progression

Chapter - 05   
Mathematics Lab Activity Class X

Mathematics Laboratory Activities on Arithmatic Progression for class X students with complete observation tables strictly according to the CBSE syllabus.

arithmatic progression
Activity - 06

Objective

To find the sum of the first n odd natural numbers.


Material Required

Cardboard, thermocol balls, pins, pencil, ruler, adhesive, white paper.

Procedure

1. Take a piece of cardboard of a convenient size and paste a white paper on it.

2. Draw a square of suitable size on it (10 cm × 10 cm).

3. Divide this square into unit squares.

Figure 1

4. Fix a thermocol ball in each square with the help of a pin as shown in Fig. 1.

5. Enclose the balls as shown in the figure.

6. Starting from the uppermost right corner, the number of balls in first enclosure

(blue colour) = 1 = (12).

7. The number of balls in first 2 enclosures = 1 + 3 = 4 = (22).

8. The number of balls in first 3 enclosures = 1 + 3 + 5 = 9 = (32).

9. The number of balls in first 10 enclosures = 1 + 3 + 5 + ... + 19 = 100 = (102).

10. This gives the sum of first ten odd natural numbers. This result can be generalised for the sum of first n odd numbers as:

Sn = 1 + 3 + ......... + (2n – 1) = n2


Observations

Sn = 1 + 3 + ......... + (2n – 1) = n2      …………… (1)

For n = 4, S4             =  42    = 16

For n = 12, S12         =  122  = 144

For n = 50, S50         =  502  = 2500

For n = 100, S100 =  1002 = 10000

Result

Sum of first n odd natural number is given by n2 where n is the number of terms.    

Applications

The activity is useful in determining formula for the sum of the first n odd natural numbers.



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